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There was an issue in the as_dict method of protocol base where it wasn't ever explicitly checking for subclasses of ProtocolBase and calling as_dict for them. This makes the check explicity, rather than implicit (by checking for other conditions or the existence of 'as_dict')
cwacek
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Mar 9, 2016
bugfix: Fixes #35 and adds a test case to check it.
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There was an issue in the as_dict method of protocol base
where it wasn't ever explicitly checking for subclasses
of ProtocolBase and calling as_dict for them. This makes
the check explicity, rather than implicit (by checking for other
conditions or the existence of 'as_dict')