//

// Created by zing on 4/1/2020.

//

#include <iostream>

#include <bitset>

int main() {

int x{012}; // 0 before the number means this is octal

std::cout << x << "\n";

int x2{0xF}; // 0x before the number means this is hexadecimal

std::cout << x2 << "\n";

int bin{};

bin = 0b1; // assign binary 0000 0001 to the variable

bin = 0b11; // assign binary 0000 0011 to the variable

bin = 0b1010; // assign binary 0000 1010 to the variable

bin = 0b11110000; // assign binary 1111 0000 to the variable

//C ++ 14

int bin2{ 0b1011'0010 }; // assign binary 1011 0010 to the variable

long value{ 2'132'673'462 }; // much easier to read than 2132673462

int x3 { 12 };

std::cout << x3 << '\n'; // decimal (by default)

std::cout << std::hex << x3 << '\n'; // hexadecimal

std::cout << x3 << '\n'; // now hexadecimal

std::cout << std::oct << x3 << '\n'; // octal

std::cout << std::dec << x3 << '\n'; // return to decimal

std::cout << x3 << '\n'; // decimal

// std::bitset<8> means we want to store 8 bits

std::bitset<8> bin1{ 0b1100'0101 }; // binary literal for binary 1100 0101

std::bitset<8> bin3{ 0xC5 }; // hexadecimal literal for binary 1100 0101

std::cout << bin1 << ' ' << bin2 << '\n';

std::cout << std::bitset<4>{ 0b1010 } << '\n'; // we can also print from std::bitset directly

return 0;

}