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74 lines (60 loc) · 3.82 KB
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# SOME DESCRIPTIVE TITLE.
# Copyright (C) 2001-2025, Python Software Foundation
# This file is distributed under the same license as the Python package.
# FIRST AUTHOR <EMAIL@ADDRESS>, YEAR.
#
#, fuzzy
msgid ""
msgstr ""
"Project-Id-Version: Python 3.13\n"
"Report-Msgid-Bugs-To: \n"
"POT-Creation-Date: 2025-02-14 14:17+0000\n"
"PO-Revision-Date: 2021-06-28 00:56+0000\n"
"Language-Team: Persian (https://app.transifex.com/python-doc/teams/5390/fa/)\n"
"MIME-Version: 1.0\n"
"Content-Type: text/plain; charset=UTF-8\n"
"Content-Transfer-Encoding: 8bit\n"
"Language: fa\n"
"Plural-Forms: nplurals=2; plural=(n > 1);\n"
#: ../../library/codeop.rst:2
msgid ":mod:`!codeop` --- Compile Python code"
msgstr ""
#: ../../library/codeop.rst:10
msgid "**Source code:** :source:`Lib/codeop.py`"
msgstr ""
#: ../../library/codeop.rst:14
msgid "The :mod:`codeop` module provides utilities upon which the Python read-eval-print loop can be emulated, as is done in the :mod:`code` module. As a result, you probably don't want to use the module directly; if you want to include such a loop in your program you probably want to use the :mod:`code` module instead."
msgstr ""
#: ../../library/codeop.rst:20
msgid "There are two parts to this job:"
msgstr ""
#: ../../library/codeop.rst:22
msgid "Being able to tell if a line of input completes a Python statement: in short, telling whether to print '``>>>``' or '``...``' next."
msgstr ""
#: ../../library/codeop.rst:25
msgid "Remembering which future statements the user has entered, so subsequent input can be compiled with these in effect."
msgstr ""
#: ../../library/codeop.rst:28
msgid "The :mod:`codeop` module provides a way of doing each of these things, and a way of doing them both."
msgstr ""
#: ../../library/codeop.rst:31
msgid "To do just the former:"
msgstr ""
#: ../../library/codeop.rst:35
msgid "Tries to compile *source*, which should be a string of Python code and return a code object if *source* is valid Python code. In that case, the filename attribute of the code object will be *filename*, which defaults to ``'<input>'``. Returns ``None`` if *source* is *not* valid Python code, but is a prefix of valid Python code."
msgstr ""
#: ../../library/codeop.rst:41
msgid "If there is a problem with *source*, an exception will be raised. :exc:`SyntaxError` is raised if there is invalid Python syntax, and :exc:`OverflowError` or :exc:`ValueError` if there is an invalid literal."
msgstr ""
#: ../../library/codeop.rst:45
msgid "The *symbol* argument determines whether *source* is compiled as a statement (``'single'``, the default), as a sequence of :term:`statement` (``'exec'``) or as an :term:`expression` (``'eval'``). Any other value will cause :exc:`ValueError` to be raised."
msgstr ""
#: ../../library/codeop.rst:52
msgid "It is possible (but not likely) that the parser stops parsing with a successful outcome before reaching the end of the source; in this case, trailing symbols may be ignored instead of causing an error. For example, a backslash followed by two newlines may be followed by arbitrary garbage. This will be fixed once the API for the parser is better."
msgstr ""
#: ../../library/codeop.rst:61
msgid "Instances of this class have :meth:`~object.__call__` methods identical in signature to the built-in function :func:`compile`, but with the difference that if the instance compiles program text containing a :mod:`__future__` statement, the instance 'remembers' and compiles all subsequent program texts with the statement in force."
msgstr ""
#: ../../library/codeop.rst:70
msgid "Instances of this class have :meth:`~object.__call__` methods identical in signature to :func:`compile_command`; the difference is that if the instance compiles program text containing a :mod:`__future__` statement, the instance 'remembers' and compiles all subsequent program texts with the statement in force."
msgstr ""