from functools import reduce

def find_2nd_num_1(num_list):

'''

方法1：直接进行逆序排序，找出第二个数即可

'''

tmp_list = sorted(num_list, reverse=True)

return tmp_list[1]

def find_2nd_num_2(num_list):

'''

方法2:传统面向过程的思路，设置两个标志位，一个存储最大值，一个存储次大值

'''

a = num_list[0]

b = num_list[0]

for i in range(1, len(num_list)):

if num_list[i] > a:

b = a

a = num_list[i]

elif num_list[i] > b:

b = num_list[i]

return b

def find_2nd_num_3(num_list):

num = reduce(lambda ot, x: ot[1]<x and (ot[1], x) or ot[0]< x

and (x, ot[1]) or ot, num_list, (0,0))[0]

return num

if __name__ == '__main__':

num_list = [34, 11, 23, 56, 78, 0, 9, 12, 3, 7, 5]

print(find_2nd_num_3(num_list))