package math; /** * Created by gouthamvidyapradhan on 02/08/2017. Given a non-negative integer num, repeatedly add * all its digits until the result has only one digit. * *
For example: * *
Given num = 38, the process is like: 3 + 8 = 11, 1 + 1 = 2. Since 2 has only one digit, return * it. * *
Follow up: Could you do it without any loop/recursion in O(1) runtime? */ public class AddDigits { public static void main(String[] args) throws Exception { System.out.println(new AddDigits().addDigits(38)); } public int addDigits(int num) { if (num == 0) return 0; return num % 9 == 0 ? 9 : num % 9; } }