Difficulty: Easy
Implement int sqrt(int x).
Compute and return the square root of x, where x is guaranteed to be a non-negative integer.
Since the return type is an integer, the decimal digits are truncated and only the integer part of the result is returned.
Example 1:
Input: 4
Output: 2
Example 2:
Input: 8
Output: 2
Explanation: The square root of 8 is 2.82842..., and since
the decimal part is truncated, 2 is returned.
Language: Java
class Solution {
public int mySqrt(int x) {
int left = 0;
int right = x;
int medium = (left + right) / 2;
while (left <= right) {
if (medium == 0) {
return right;
}
int target = x / medium;
if (medium == target || medium == target + 1) {
return target;
} else if (target < medium) {
right = medium;
} else if (target > medium - 1) {
left = medium + 1;
}
medium = (left + right) / 2;
}
return 0;
}
}