//Question 1

let x = 1;

function f1() {

let x = 2;

console.log(x);

}

console.log(x);

//Explain why line 4 and line 6 output different numbers.

//answer:

//Because x is declared before the f1() function and given a value, then inside the function scope

//x is assigned a new value and logged - this means that value is only used inside the function scope.

// Then x is once again logged outside of the function scope meaning it gets its original value from line 2.

//Question 2

let x = 10;

function f1() {

console.log(x);

let y = 20;

}

console.log(f1());

console.log(y);

//What will be the output of this code. Explain your answer in 50 words or less.

//answer:

// if it runs it will log 10 to the console but y is undefined outside of f1().

//Question 3

const x = 9;

function f1(val) {

val = val + 1;

return val;

}

f1(x);

console.log(x);

const y = { x: 9 };

function f2(val) {

val.x = val.x + 1;

return val;

}

f2(y);

console.log(y);

//What will be the output of this code. Explain your answer in 50 words or less.

//answer

// I believe it should log 9 (the original value of x) then log an object {x:9}.