Take a look at the following code:
1 let x = 1;
2 function f1()
3 {
4 let x = 2;
5 console.log(x);
6 }
7 console.log(x);
Explain why line 4 and line 6 output different numbers.
line 5 output will execute line 4 (local scope) and line 7 execute global scope variable
Take a look at the following code:
let x = 10
function f1()
{
console.log(x)
let y = 20
}
console.log(f1()) // will execute line 30 and the output will be 10
console.log(y) // ReferenceError y is not defined / y is in local scope
What will be the output of this code. Explain your answer in 50 words or less.
Take a look at the following code:
const x = 9;
function f1(val) {
val = val + 1;
return val;
}
f1(x); // this funcation is called but it can not change the x value;
console.log(x); // the output of this line is 9 (Global scope line 45)
const y = { x: 9 };
function f2(val) {
val.x = val.x + 1;
return val;
}
f2(y);
console.log(y); // the output will be { x: 10 } because line 55 is an object and in line 58 changed the value of x and not y.
What will be the output of this code. Explain your answer in 50 words or less.