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T190_reverse_bits.java
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45 lines (42 loc) · 1.2 KB
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public class Solution {
// you need treat n as an unsigned value
public int reverseBits(int n) {
int result = 0;
for (int i = 0; i < 32; i++) {
result += n & 1;
n >>>= 1; // CATCH: must do unsigned shift
if (i < 31) // CATCH: for last digit, don't shift!
result <<= 1;
}
return result;
}
}
//optimization.
// cache
// private final Map<Byte, Integer> cache = new HashMap<Byte, Integer>();
// public int reverseBits(int n) {
// byte[] bytes = new byte[4];
// for (int i = 0; i < 4; i++) // convert int into 4 bytes
// bytes[i] = (byte)((n >>> 8*i) & 0xFF);
// int result = 0;
// for (int i = 0; i < 4; i++) {
// result += reverseByte(bytes[i]); // reverse per byte
// if (i < 3)
// result <<= 8;
// }
// return result;
// }
// private int reverseByte(byte b) {
// Integer value = cache.get(b); // first look up from cache
// if (value != null)
// return value;
// value = 0;
// // reverse by bit
// for (int i = 0; i < 8; i++) {
// value += ((b >>> i) & 1);
// if (i < 7)
// value <<= 1;
// }
// cache.put(b, value);
// return value;
// }