Take a look at the following code:

1    let x = 1;
2    function f1()
3    {
4        let x = 2;
5        console.log(x);
6    }
7    console.log(x);

Explain why line 4 and line 6 output different numbers. one is global the other is local causing them to have different results

Take a look at the following code:

let x = 10

function f1()
{
    console.log(x)
    let y = 20
}

console.log(f1())
console.log(y)

10 - x undefined - y x is defined as a global variable and when we consoled (f1()) the output will be 10. y is defined inside the function and when we consoled y outside the function we will get an error "y is not defined". What will be the output of this code. Explain your answer in 50 words or less.

Take a look at the following code:

const x = 9;

function f1(val) {
  val = val + 1;
  return val;
}

f1(x);
console.log(x);

const y = { x: 9 };

function f2(val) {
  val.x = val.x + 1;
  return val;
}

f2(y);
console.log(y);

What will be the output of this code. Explain your answer in 50 words or less. 9 x: 10 f1(x) will return 10, x will stays same (9) because x is a constant and cannot be changed. The function f2(y) will return {x:10} because y is an object and object property can be changed